sql语句
select a.house_no as '房子',substring_index(substring_index(a.name,',',b.help_topic_id+1),',',-1) as '拥有者'
from aa a --aa是一个表,换成你的
join mysql.help_topic b on b.help_topic_id < (length(a.name) - length(replace(a.name,',',''))+1);
关键点
mysql.help_topic b on b.help_topic_id < (length(a.name) - length(replace(a.name,',',''))+1)
name格式:张三,李四,王五