如何将SQL中3张表计算的2个字段的值插入一张表显示6个字段?

第一张表

select place,count(*)'>4μm_NG' from [Report_Test].[dbo].[ods_QualityModule_cleanliness_recycle] 

where place ='中转油箱出口'  and substring (convert (varchar(4),test_time),0,5) ='2022' and dust1>10000 group by place

第二张表

select place,count(*)'>6μm_NG' from [Report_Test].[dbo].[ods_QualityModule_cleanliness_recycle] 

where place ='中转油箱出口'  and substring (convert (varchar(4),test_time),0,5) ='2022' and dust2>640 group by place

第三张表

select place,count(*)'>14μm_NG' from [Report_Test].[dbo].[ods_QualityModule_cleanliness_recycle] 

where place ='中转油箱出口'  and substring (convert (varchar(4),test_time),0,5) ='2022' and dust3>160 group by place 

阿聪聪 发布于 2023-1-7 14:31 (编辑于 2023-1-7 14:31)
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最佳回答
1
MKERALv6初级互助
发布于2023-1-7 15:26(编辑于 2023-1-7 15:43)

是这种效果?

效果一:
place>4μm_NG>6μm_NG>14μm_NG
中转油箱出口152030

如果是直接使用left join 将三段SQL拼起来就行

效果二:
place>4μm_NGplace>6μm_NGplace>14μm_NG
中转油箱出口15中转油箱出口20中转油箱出口30

第二种的话:

select a.*,b.*,c.*from(

select '1' as a ,place,count(*)'>4μm_NG' from [Report_Test].[dbo].[ods_QualityModule_cleanliness_recycle] 

where place ='中转油箱出口'  and substring (convert (varchar(4),test_time),0,5) ='2022' and dust1>10000 group by place

) as a

left join (

select '1' as a ,place,count(*)'>6μm_NG' from [Report_Test].[dbo].[ods_QualityModule_cleanliness_recycle] 

where place ='中转油箱出口'  and substring (convert (varchar(4),test_time),0,5) ='2022' and dust2>640 group by place

) as b on a.a=b.a

left join(

select '1' as a ,place,count(*)'>14μm_NG' from [Report_Test].[dbo].[ods_QualityModule_cleanliness_recycle] 

where place ='中转油箱出口'  and substring (convert (varchar(4),test_time),0,5) ='2022' and dust3>160 group by place 

) as on a.a=c.a

最佳回答
0
keyw1066Lv3见习互助
发布于2023-1-7 15:52

有个思路是先union,然后使用case when

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