那就不使用JQ了。用原生js来请求
function ajaxPost(url, data, callback) {
var xhr = new XMLHttpRequest();
xhr.open('POST', url, true);
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
xhr.send(data);
xhr.onreadystatechange = function () {
if (xhr.readyState == 4 && xhr.status == 200) {
callback(xhr.responseText);
}
}}
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